JPSC Recruitment 2018 for Assistant Engineer – 57 Posts.

By | September 16, 2018

JPSC Recruitment 2018:

Jharkhand Public Service Commission (JPSC), invites applications from Indian citizens for the post of Assistant Engineer Civil / Mechanical, more detail related to post are given below:

JPSC Recruitment 2018

Total No of Posts: 57 Posts.

Name of Post and Education Qualifications:

➽  Assistant Engineer (Civil): 48 Posts

➽  Assistant Engineer (Mechanical): 09 Posts

Education Qualifications:

Bachelor’s Degree in Civil / Mechanical in Engineering or Technology or equivalent qualification from a recognized University of the Union or State Government.

Age Limits: A candidate must have minimum 21 years and Not exceeded the age of 35 years as on 25/01/2016. Relaxation in age limits will be given as per applicable rules.

Application Fees: Rs. 600/- as application fee cum Bank charges for Unreserved and OBC (NCL) category and Rs. 150/- as Bank charges for SC/ ST/ PwD candidates. 

Panchayati Raj Department Recruitment 2018 for Technical Assistant – 2096 Posts.

BSF Recruitment 2018 for Sub Inspector and Junior Engineer – 139 Posts

How to Apply:

First go to the JPSC’s website: www.jpsc.gov.in then click on Online Application tab and after that, click on the link for the concerned online application. The link will redirect to the first page of the online application form.

Important Dates:
  • Commencement of registration: 14/09/2018.
  • Last date of registration: 29/10/2018.
  • Last date of depositing examination fee: 31/10/2018.
  • Last date for Submission of Hard copy of Application form with relevant Documents: 12/11/2018.
Important Links:

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2 thoughts on “JPSC Recruitment 2018 for Assistant Engineer – 57 Posts.

  1. Engineering Recruitment

    No, Please Read Below Note Given in Advertisement.
    (नोट- अभ्यर्थी परीक्षा के लिए आवेदन करने की अंतिम तिथि को न्यूनतम शैक्षणिक योग्यता अनिवार्यतः प्राप्त कर)
    (Note: To get the minimum educational qualification for the last date of applying for the candidate's examination)

    Reply

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